q^2=0.22

Solution for q^2=0.22 equation:

q^2=0.22

We move all terms to the left:

q^2-(0.22)=0

We add all the numbers together, and all the variables

q^2-0.22=0

a = 1; b = 0; c = -0.22;
Δ = b2-4ac
Δ = 02-4·1·(-0.22)
Δ = 0.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.88}}{2*1}=\frac{0-\sqrt{0.88}}{2}
=-\frac{\sqrt{}}{2}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.88}}{2*1}=\frac{0+\sqrt{0.88}}{2}
=\frac{\sqrt{}}{2}
$